গুরুত্বপুর্ণ সিভিল ইঞ্জিনিয়ারিং ক্যালকুলেশন

Md. Ashraful Haque, 16-May-2008
ভিউ : 36495

Usefull Civil Engineering Calculation

CONCRETE GRADE:
M5 = 1:4:8
M10= 1:3:6
M15= 1:2:4
M20= 1:1.5:3
M25= 1:1:2

Weight of Engineering Materials

1.Bitumen - 1340 Kg / M3

2.Cement- 1440 Kg / M3

3.Gold - 19224 Kg / M3

4.Ice -913 Kg / M3

5.Wrought Iron -7700 Kg / M3

6.Pig Iron - 7200 Kg / M3

7.Cast Iron - 7650 Kg / M3

8.Lead - 11374 Kg / M3

9.A.C Sheets- 17 kg / M2

10.Petrol â€“ 690 Kg / M3

CLEAR COVER TO MAIN REINFORCEMENT:
1.FOOTINGS : 50 mm
2.RAFT FOUNDATION.TOP : 50 mm
3.RAFT FOUNDATION.BOTTOM/SIDES : 75 mm
4.STRAP BEAM : 50 mm
5.GRADE SLAB : 20 mm
6.COLUMN : 40 mm
7.SHEAR WALL : 25 mm
8.BEAMS : 25 mm
9.SLABS : 15 mm
10.FLAT SLAB : 20 mm
11.STAIRCASE : 15 mm
12.RET. WALL : 20/ 25 mm on earth
13.WATER RETAINING STRUCTURES : 20/30 mm

WEIGHT OF ROD PER METER LENGTH:
DIA WEIGHT PER METER

6mm = 0.222Kg
8mm = 0.395 Kg
10mm = 0.616 Kg
12mm = 0.888 Kg
16mm = 1.578 Kg
20mm = 2.466 Kg
25mm = 3.853 Kg
32mm = 6.313 Kg
40mm = 9.865 Kg

1bag cement-50kg
1feet-0.3048m
1m-3.28ft
1sq.m-10.76sq.ft
1cu.m-35.28cu.ft
1acre-43560sq.ft
1cent-435.6sq.ft
1hectare-2.47acre
1acre-100cent-4046.724sq.m
1ground-2400sq.ft
1unit-100cu.ft- 2.83cu.m 1square-100sq.ft

1 M LENGTH STEEL ROD I ITS VOLUME
V=(Pi/4)*Dia x DiaX L=(3.14/4)x D x D X 1 (for
1m length) Density of Steel=7850 kg/ cub meter
Weight = Volume x Density=(3.14/4)x D x D X
1Ã—7850 (if D is in mm ) So = ((3.14/4)x D x D X
1Ã—7850)/(1000Ã—1000) = Dodd/162.27

DESIGN MIX:
M10 ( 1 : 3.92 : 5.62)
Cement : 210 Kg/ M 3
20 mm Jelly : 708 Kg/ M 3
12.5 mm Jelly : 472 Kg/ M 3
River sand : 823 Kg/ M 3
Total water : 185 Kg/ M 3

Fresh concrete density: 2398 Kg/M 3
M20 ( 1 : 2.48 : 3.55)
Cement : 320 Kg/ M 3
20 mm Jelly : 683 Kg/ M 3
12.5 mm Jelly : 455 Kg/ M 3
River sand : 794 Kg/ M 3
Total water : 176 Kg/ M 3
Admixture : 0.7%

Fresh concrete density: 2430 Kg/ M 3
M25 ( 1 : 2.28 : 3.27)
Cement : 340 Kg/ M 3
20 mm Jelly : 667 Kg/ M 3
12.5 mm Jelly : 445 Kg/ M 3
River sand : 775 Kg/ M 3
Total water : 185 Kg/ M 3
Admixture : 0.6%
Fresh concrete density: 2414 Kg/ M 3
Note: sand 775 + 2% moisture, Water185 -20.5 =
164 Liters,
Admixture = 0.5% is 100ml
M30 ( 1 : 2 : 2.87)
Cement : 380 Kg/ M 3
20 mm Jelly : 654 Kg/ M 3
12.5 mm Jelly : 436 Kg/ M 3
River sand : 760 Kg/ M 3
Total water : 187 Kg/ M 3
Admixture : 0.7%
Fresh concrete density: 2420 Kg/ M 3
Note: Sand = 760 Kg with 2% moisture(170.80+15.20)
M35 ( 1 : 1.79 : 2.57)
Cement : 410 Kg/ M 3
20 mm Jelly : 632 Kg/ M 3
12.5 mm Jelly : 421 Kg/ M 3
River sand : 735 Kg/ M 3
Total water : 200 Kg/ M 3
Admixture : 0.7%
Fresh concrete density: 2400 Kg/ M 3
Note: sand = 735 + 2%, Water = 200- 14.7 =
185.30,
Admixture = 0.7%
M40 ( 1 : 1.67 : 2.39)
Cement : 430 Kg/ M 3
20 mm Jelly : 618 Kg/ M 3
12.5 mm Jelly : 412 Kg/ M 3
River sand : 718 Kg/ M 3
Water Cement ratio : 0.43
Admixture : 0.7%
Note: Sand = 718 + Bulk age 1%
M45 ( 1 : 1.58 : 2.26)
Cement : 450 Kg/ M 3
20 mm Jelly : 626 Kg/ M 3
12.5 mm Jelly : 417 Kg/ M 3
River sand : 727 Kg/ M 3 + Bulk age 1%
Water Cement ratio : 0.43
Admixture : 0.7%
M50 ( 1 : 1.44 : 2.23)
Cement : 450 Kg/ M 3
20 mm Jelly : 590 Kg/ M 3
12.5 mm Jelly : 483 Kg/ M 3
River sand : 689 Kg/ M 3 + Bulk age 12%
Water Cement ratio : 0.36 (188 Kg)
Admixture : 1.20%3
Micro silica : 30 Kg
Super flow 6.7% of cement
1 cubic meter contains 500 bricks
The Standard size of the 1st class brick is 190mmx 90mm x90mm and motor joint should be 10mm thick
So brick with motor=200 x 100 x 100.
Volume of 1st class brick = 0.19 x 0.09 X 0.09 =0.001539 cu.m
Volume of 1st class brick with motor =0.2 x 0.1 x0.1=0.002 cu.m
No. on bricks per 1cu.m= 1/volume of1st class brick with motor =1/0.002 = 500 no's of bricks

STANDARD CONVERSION FACTORS
INCH = 25.4 MILLIMETRE
FOOT = 0.3048 METRE
YARD = 0.9144 METRE
MILE = 1.6093 KILOMETER
ACRE = 0.4047 HECTARE
POUND = 0.4536 KILOGRAM
DEGREE FARENHEIT X 5/9 â€“ 32 = DEGREE CELSIUS
MILLIMETRE= 0.0394 INCH
METRE = 3.2808FOOT
METRE = 1.0936YARD

A rope having length 100cm.You can form any shape using this rope (Example: Triangle, Rectangle, etc.,). Which shape will covers maximum area

1 Newton = o.101971 kg
1 mm2 = 0.01 cm2
1 cm2 = 100 mm2
1 mm2 = 20 N
100 mm2 = 2000N
1 cm2 = 2000N
2000 N = 203.942 kg
So 20 N/ mm2 = 203.942 kg / cm2
RATIO IS 1:1.5:3
then volume is 1+1.5+3=5.5 and the total volume for using mix=1.57 m3 then cement required

মন্তব্য সমুহ